An object with a mass of 35 kg accelerates at 0.7 m/s^2 to the right, as shown in the diagram.

Daftar Isi

An object with a mass of 35 kg accelerates at 0.7 m/s^2 to the right, as shown in the diagram.

There are four forces acting on the object.

A. Find the value of X
B. Calculate the value of Y​

Jawaban

Certainly, let's calculate the forces X and Y acting on the object.

Given:

• Mass (m) = 35 kg
• Acceleration (a) = 0.7 m/s^2 to the right
• Force 1 (F1) = 70 N to the left
• Force 2 (F2) = 20 N to the right
• Force 3 (F3) = 320 N downwards

A. Find the value of X

We can use Newton's second law of motion to find the net force acting on the object:

Net force = mass * acceleration

Since the object is accelerating to the right, the net force must also be to the right. Therefore, we can set up the equation:

X - F1 - F2 = m * a

Substituting the given values:

X - 70 N - 20 N = 35 kg * 0.7 m/s^2

Solving for X:

X = (35 kg * 0.7 m/s^2) + 70 N + 20 N
X = 24.5 N + 70 N + 20 N
X = 114.5 N

Therefore, the value of force X is 114.5 N to the right.

B. Calculate the value of Y

Since there is no vertical acceleration of the object, the net vertical force must be zero. Therefore, we can set up the equation:

Y - F3 = 0

Substituting the given value of F3:

Y - 320 N = 0

Solving for Y:

Y = 320 N

Therefore, the value of force Y is 320 N upwards.

Summary:

• X = 114.5 N (to the right)
• Y = 320 N (upwards)

Let me know if you have any other questions!